x^2+14x-9.6=0

Solution for x^2+14x-9.6=0 equation:

x^2+14x-9.6=0

a = 1; b = 14; c = -9.6;
Δ = b2-4ac
Δ = 142-4·1·(-9.6)
Δ = 234.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-\sqrt{234.4}}{2*1}=\frac{-14-\sqrt{234.4}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+\sqrt{234.4}}{2*1}=\frac{-14+\sqrt{234.4}}{2}
$